If the mean of 5 integers is 17, what is the largest possible number if they are all positive and none are repeated?
hi
Tricky question :D You know how to get averages?
yes
sum/#of #s
You put it very strangely, Just to be clear, uhh what's the average of 3, 5, and 7?
5
Okay, good. ^^ Now let's see how to go about this question... Hang on.
ok
Okay, I got it. Usually, if you want a really big number to be part of a set you're trying to get the average of, you need really small numbers to balance it out :D So, how about we have four small numbers and one really large number, and try to make them have an average of 17. Sound good?
ok
Okay, read your question, and give me the four LOWEST possible numbers that could be part of your set of five numbers.
ok wait
85,84,83,82
Ahem. Seriously? XD
16,15,14,13
Uhh, the infinity of numbers do not allow much room for guessing :P C'mon... We're talking POSITIVE INTEGERS and NO REPETITIONS. What are the four LOWEST possible numbers that fit those criteria?
please help me
I am helping you ^^ But I can only help you so much, you know. You need to help yourself too. I'll make it easy. What is the LOWEST POSITIVE INTEGER?
0
But 0 is not a positive number.
mathmole get out
1
Be nice, now. You have a rather bad choice of people to badmouth .... and yes, that is the lowest. And while we'd love to have four 1's in our set, the rules don't allow for repetitions. So what's another low positive integer we can use?
2
See the pattern? Now, all I'm asking for are the four LOWEST positive integers. C'mon. You know them. What are they? ^^
1,2,3,4,80
i got my answer
80 is the answer?
Is it? Find out. Get the average of 1, 2, 3, 4, and 80. Is it 17?
its 18
my answer is 75
Wasn't so hard, now, was it? :P Good job, anyway :D
thank you
i have another question ok
@terenzreignz : You did a really fine job here, especially in the way you involved URMOMA in finding the solution and beginning with very small positive numbers. Good work!
i will post another question
If you have another question, post it separately from this one, please.
@mathmale Thank you ^^ I learned my lesson since I first joined up :D
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