Evaluate S5 for 300 + 150 + 75 + … and select the correct answer\below.
18.75
93.75
581.25
145.3125
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
Hayhayz (hayhayz):
@imqwerty
imqwerty (imqwerty):
alright what kind of series do you think it is
Hayhayz (hayhayz):
geometric series
OpenStudy (anonymous):
hi guy's
imqwerty (imqwerty):
yes correct
and the formula for the sum till \(n^{th}\) term of a geometric series is this-
\(\large Sum=a \left( \frac{1-r^n}{1-r} \right)\)
here \(a\) is the 1st term
and r is the common ratio
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
gm, find, first 5 term of this series
OpenStudy (anonymous):
find common ratio, and than find term's of this series,
and after this use formula as mentioned aove in @imqwerty comment
Hayhayz (hayhayz):
what would the common ratio be?
imqwerty (imqwerty):
the common ratio is the ratio of any two consecutive terms
like this->
\(common ~ratio= \large \frac{2^{nd}~term}{1^{st}~term}\)
OpenStudy (anonymous):
devide first term of the series with second term, and the answer would be yours C.R.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
sorry, second by first,
OpenStudy (anonymous):
mistake, excuses
imqwerty (imqwerty):
you can take any two consecutive terms
so this is also correct-
\(common~ratio=\large \frac{3^{rd}~term}{2^{nd}~term}\)
Hayhayz (hayhayz):
so 0.5?
OpenStudy (anonymous):
yes right
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
imqwerty (imqwerty):
yes :)
Hayhayz (hayhayz):
Using the formula you put what do i plug in for the n? 5?
imqwerty (imqwerty):
yeah
you need to find "\(S5\)" meaning sum till the 5th term
so yeah \(n=5\) in our case :)
Hayhayz (hayhayz):
I'll tag you if I need help on more. Thanks qwerty :D