Question

log question

Answer 1

\[\frac{ \log_{b}a }{ \log_{c}a }=\frac{ 19 }{ 99 }, then \frac{ b }{ c }=c^k\]

compute for k exactly

Answer 2

is that last equation right?

Answer 3

is one of those c's suppose to be a?

Answer 4

no

Answer 5

k = 80/19 ?

Answer 6

\[\dfrac{b}{c} = c^k \implies k = \log_c\frac{b}{c} = \log_c b - 1\]

Answer 7

could be \[\log_b(a)=\frac{\log(a)}{\log(b)}\]