Question

Find the area of the region that lies inside the first curve and outside the second curve.
r^2 = 8 cos 2theta , r = 2

so this is a leminscate

Answer 1

4 = 8 cos 2theta
1/2 = cos 2theta
theta = pi/6

Answer 2

dude r=2 is a circle

Answer 3

oh right

Answer 4

anyways i set it up
but im off by a bit...

Answer 5

\[\int\limits_{0}^{\pi/6} (8\cos2 \theta)^2 - (2)^2 d \theta\]

Answer 6

@ganeshie8 what am i doing wrong here? i keep getting the wrong answer no matter how i set it up..

Answer 7

\[1/2 \int\limits_{-\pi/6}^{\pi/6} 8\cos 2\theta - 4~ d \theta\]