Find the area of the region that lies inside the first curve and outside the second curve.
r^2 = 8 cos 2theta , r = 2

so this is a leminscate

Question

Find the area of the region that lies inside the first curve and outside the second curve.
r^2 =  8  cos 2theta , r = 2

so this is a leminscate

shamil98 · Answer

4 = 8 cos 2theta
1/2 = cos 2theta
theta = pi/6

inkyvoyd · Answer

dude r=2 is a circle

shamil98 · Answer

oh right

shamil98 · Answer

anyways i set it up
but im off by a bit...

shamil98 · Answer

$$\int\limits_{0}^{\pi/6} (8\cos2 \theta)^2 - (2)^2 d \theta$$

shamil98 · Answer

@ganeshie8 what am i doing wrong here? i keep getting the wrong answer no matter how i set it up..

shamil98 · Answer

$$1/2 \int\limits_{-\pi/6}^{\pi/6} 8\cos 2\theta - 4~ d \theta$$