Factoring a trinomial please help me solve this -x^2 + 14x - 45
Me personally I would multiply everything by -1 right off the bat
Than the-x^2 will be positive so it will be a little easier to figure out
but...doesn't this need to end up in parentheses? a solved a different one earlier and the answer ended up looking like this: (n-18) (n+4)
Yes: If you follow kayders' advice, you'll get (-1)(x^2 - 14x - 45). Yes, to complete this factoring you must factor x^2 - 14x - 45.
Yes it needs to end up in parenthesis but you need to find two numbers that multiply to -45 and add to 14x if you don't want to multiply by the -1
What are sets of integer factors of 45? Which set could add up to 14?
What are sets of integer factors of -45? Which set could add up to -14?
Wait mathdale
i think you both have the numbers a little bit mixed up. after the -1 it ends up like this right? \[x ^{2} - 14 + 45\] (just for my own clarification.)
Wouldn't it be multiply to 45 that adds up to -14 if you multiply by the -1
Don't forget your x with the -14 so -14x
yep just went a little too fast. I know it's there
Okay good now what is two numbers that multiply to 45
"Yes: If you follow kayders' advice, you'll get (-1)(x^2 - 14x - 45). Yes, to complete this factoring you must factor x^2 - 14x - 45." I'm sticking with my previous statement. (-1) becomes just another factor of the original expression. Still have to factor x^2 - 14x - 45.
these are the only ones I could come up with 5x9 3x15 45x1
Good now which one can add to 14 remember it has to be -14x
- (x - 9) (x - 5) what do you think?
The three factors are (-1), ( ) and ( ). Bookish One: You could check that yourself, and I strongly encourage you to do so.
yes good
That's the answer :)
thank you for your help!
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*your asking
*you're asking ;)
Not the best at grammar :P I'm a math person
same for me except the other way around XD
Lol everyone is good at their own subjects :)
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