Question

how do u prove the identity of :
tan x* cos^2 x -cot x* sin^ 2 x=0 ???

Answer 1

try using these identities
\[\tan(x) = \frac{\sin(x)}{\cos(x)}, \cot (x) = \frac{\cos(x)}{\sin(x)}\]

Answer 2

but wat do i do with sin^2 x

Answer 3

sin^2x or \[\sin^2(x) \] can also be written as
\[\sin^2x = (sinx)(sinx) \]
because that notation means to write sin x twice

Answer 4

Fair warning though
\[\sin^2x \] and \[\sin2x \]
ARE DIFFERENT!

\[\sin^2x = (sin(x))(sin(x)) \] and \[\sin2x = 2sinxcosx \]

Answer 5

another hint: a cos x cancels for tan x* cos^2 x
and a sinx cancels for cot x* sin^ 2 x
afterwards the proof would be almost complete

Answer 6

after you substitute for tan and cot,
terms will cancel.