Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ibrafacts):
Question
OpenStudy (ibrafacts):
2
OpenStudy (photon336):
Well all you need to do is multiply the number of moles times the heat of vaporization for water.
\[0.75~grams*(\frac{ mol }{ 18grams })*(40.79*10^{3}J/mole) = energy~total\]
OpenStudy (ibrafacts):
oh
OpenStudy (ibrafacts):
did i mess up number 2?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ibrafacts):
its number 2 the same as number 1 but just a little different
OpenStudy (ibrafacts):
didnt i do number 2 right?
OpenStudy (ibrafacts):
@Photon336 u still here?
OpenStudy (anonymous):
i think he is AFK
OpenStudy (ibrafacts):
lol
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (photon336):
I can't understand what you wrote at the end
OpenStudy (photon336):
But, you set it up correctly. I just converted mine to joules.
OpenStudy (ibrafacts):
oh how would u do number 3?
OpenStudy (photon336):
pretty sure you can set up a ratio you need to first find the molar mass of that compound.
OpenStudy (photon336):
because remember, the hint here is molar enthalpy of vaporization. then i will continue to guide you.
Still Need Help?
Join the QuestionCove community and study together with friends!