Ask your own question, for FREE!
Chemistry 21 Online
OpenStudy (ibrafacts):

Help me plz

OpenStudy (ibrafacts):

Question

OpenStudy (ibrafacts):

2

OpenStudy (photon336):

Well all you need to do is multiply the number of moles times the heat of vaporization for water. \[0.75~grams*(\frac{ mol }{ 18grams })*(40.79*10^{3}J/mole) = energy~total\]

OpenStudy (ibrafacts):

oh

OpenStudy (ibrafacts):

did i mess up number 2?

OpenStudy (ibrafacts):

its number 2 the same as number 1 but just a little different

OpenStudy (ibrafacts):

didnt i do number 2 right?

OpenStudy (ibrafacts):

@Photon336 u still here?

OpenStudy (anonymous):

i think he is AFK

OpenStudy (ibrafacts):

lol

OpenStudy (photon336):

I can't understand what you wrote at the end

OpenStudy (photon336):

But, you set it up correctly. I just converted mine to joules.

OpenStudy (ibrafacts):

oh how would u do number 3?

OpenStudy (photon336):

pretty sure you can set up a ratio you need to first find the molar mass of that compound.

OpenStudy (photon336):

because remember, the hint here is molar enthalpy of vaporization. then i will continue to guide you.

OpenStudy (ibrafacts):

yeah idk how to set it up

OpenStudy (ibrafacts):

wait i will try first

OpenStudy (ibrafacts):

|dw:1458181599065:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!