Question

y=5/8sin(-8pi/3 x)
Find the period

Answer 1

The period is equal to 2pi/B in the equation Asin(B(x+C))+D, so in this equation B is -8pi/3. So the period is equal to (2pi)/(-8pi/3) which is -6/8.

Answer 2

@trainwrecking could you show me the process of getting the answer?

Answer 3

Study Chart

Answer 4

@Directrix I know how to do the problem, I just didn't get the correct answer. I want to know where exactly I went wrong if possible

Answer 5

@trainwrecking Is the period + 3/4 rather than -3/4?

Answer 6

@Directrix You're totally right, I left out the absolute value, thanks!

@hdrager \[\frac{ 2\pi }{ \left| \frac{ -8\pi }{ 3 } \right|} = 2\pi*\frac{ 3 }{ 8\pi } = \frac{ 6 }{ 8 } = \frac{ 3 }{ 4 }\] Does that help?

Answer 7

@trainwrecking Yes thank you I get where I went wrong now

Answer 8

To get the period:

1) Write the equation in this form:

F(x) = A*sin(B*x – C) + D

2) Period of the sine function will be the "regular period" of the sine function ( 2 pi) divided by the absolute value of the coefficient of the x term, B.