Researchers estimate that 21.5% of men and 17% of women smoke. 70.2/100000 men develop lung cancer and 50.5/100000 women 90% of men who have lung cancer are smokers and 80% of women Given that a man has lung cancer, what is the probability that he is a smoker? Write this event with the correct conditional notation
Hello
HI, do u know how to answer this?
Okay thanks
why do you keep deleting your posts?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @frankystein3056 why do you keep deleting your posts? \(\color{#0cbb34}{\text{End of Quote}}\) I can't help, but if I comment I will keep getting notifications e_e
okay...
Sorry! I don't mean to confuse you. :( I do want you to get help though :)
no dont worry about it, I got ya, help would be great though- Im really stuck : (
I dont understand who in the world decides to stick statistics into geometry and call it geometry!
thankyou
\(\color{#0cbb34}{\text{Originally Posted by}}\) @frankystein3056 I dont understand who in the world decides to stick statistics into geometry and call it geometry! \(\color{#0cbb34}{\text{End of Quote}}\) Oh gosh xD that sounds terrible I'm sorry :(
dont applogize- not your fault
Alright, a math pro is here • good luck!! ♣
@frankystein3056 > I dont understand who in the world decides to stick statistics into geometry and call it geometry! This is not a Geometry problem. It is a conditional probability problem.
Yes I know, it is statistics, but it is included in geometry class for some reason
You said that twice lol
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Directrix @frankystein3056 > I dont understand who in the world decides to stick statistics into geometry and call it geometry! This is not a Geometry problem. It is a conditional probability problem. \(\color{#0cbb34}{\text{End of Quote}}\) Can you help with conditional probability though? :( sorry I'm rather rusty with this subject material
\(\color{#0cbb34}{\text{Originally Posted by}}\) @frankystein3056 Researchers estimate that 21.5% of men and 17% of women smoke. 70.2/100000 men develop lung cancer and 50.5/100000 women 90% of men who have lung cancer are smokers and 80% of women Given that a man has lung cancer, what is the probability that he is a smoker? Write this event with the correct conditional notation \(\color{#0cbb34}{\text{End of Quote}}\) http://mathforum.org/library/drmath/view/56684.html I found this, don't know if it will help but... :/
thankyou
Hello would you please be able to help me with conditional property? If not its okay I understand- its really hard.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @frankystein3056 Hello would you please be able to help me with conditional property? If not its okay I understand- its really hard. \(\color{#0cbb34}{\text{End of Quote}}\) I think it's better if you tag who you're talking to lol :P
@jomc4 - do you know conditional probability?
@agent0smith would you be able to help me with conditional probability?
alright do you want the formula or me to answer the original question..
The origininal question would be helpful
*original
We need P(smoker GIVEN lung cancer) We do not care about any of the female numbers. http://maths.nayland.school.nz/Year_13_Maths/3.13_Probability/Images_3.3_Probability/Probab15.jpg
So how do we plug it in? Also the 90% throws me off bc is that the union or is that the given?
@agent0smith are you able to help me?
Yeah I hate this question. I think the 90% gives us P(smoker AND lung cancer) = 0.9*70.2/100000
but that would be 87.75- everything im getting is over 1
If that's over 1 then you did something very wrong
I thought I'd worked it out, then I ended up with 0.9. UGH.
i think .9 is right- can you show me how you worked it out? @agent0smith? sorry im late with this
I made a table like in that link posted earlier
would you be able to show me the work possibly?
@agent0smith
I can't really since I'm on my phone. But it just didn't seem right since it ended back at 0.9
well that would make sense because it says that the probability of someone who has cancer having smoked is 90% if u proved that that makes sense
and that shows it is a conditional probability i just need to see how you got that to make sure
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