$Y_1~N(5,1)$
$Y_2~N(4,3)$
$Y_1,Y_2$ are independent.
find $P(Y_1Y_2)$
I got 0.5987 but the answer from the book is 0.6915. Please, help

Question

$Y_1~N(5,1)$
$Y_2~N(4,3)$
$Y_1,Y_2$ are independent.
find $P(Y_1>Y_2)$
I got 0.5987 but the answer from the book is 0.6915. Please, help

loser66 · Answer

Let $U = Y_1-Y_2$~ N(1,4)
Hence P(U>0) = 0.5987 (from calculator)

loser66 · Answer

@Zarkon , please.

zarkon · Answer

your calculator probably uses the standard deviation as an input and not the variance

your standard deviation is 2...use that number in your calculator

zarkon · Answer

the notation is $$X\sim N(\mu,\sigma^2)$$

loser66 · Answer

I got you. 
Just make the information clear. So standard deviation =$\sqrt {variance}$, right, that is where 2 come from, right?

zarkon · Answer

yes

loser66 · Answer

Thanks a lot. I am glad to have you as my Mentor. :)