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\(Y_1~N(5,1)\) \(Y_2~N(4,3)\) \(Y_1,Y_2\) are independent. find \(P(Y_1>Y_2)\) I got 0.5987 but the answer from the book is 0.6915. Please, help
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Let \(U = Y_1-Y_2\)~ N(1,4) Hence P(U>0) = 0.5987 (from calculator)
@Zarkon , please.
your calculator probably uses the standard deviation as an input and not the variance your standard deviation is 2...use that number in your calculator
the notation is \[X\sim N(\mu,\sigma^2)\]
I got you. Just make the information clear. So standard deviation =\(\sqrt {variance}\), right, that is where 2 come from, right?
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yes
Thanks a lot. I am glad to have you as my Mentor. :)
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