*MEDAL AND FAN* Find the common factor of the monomials. a^2b^3, ab^3
Important thing to remember on these is your property of exponentials a ^ x ( a ^y) = a^x+y
Huh? Sorry, I'm not quite understanding what you're saying.
Both terms have a common base numerical exponent with respect to the properties
Yes.
If you have a to some power x and you multiply by another factor a to some other power call it y , the product will still have base a and the exponent will be x+y
So a is factor of both judging from the bases but both terms also have a numerical factor in there exponents
What could you factor out of both terms know that multiplying the factors in the end will end up with a submation of the exponential parts?
I'm sorry, I meant to say greatest common factor.
I thought that's what you meant..
My question for you is still relevant
I hate to admit this, but the words you're using are too big.
What class is this for?
Pre-Algebra.
And what's your age may I ask?
14.
okay, there's a rule in pre-algebra when you have a number like 2 for instance and it is raised to the 3rd power that means 2 times 2 times 2 right which is?
8
So 2^3 = 8 Now the rule deals with exponents, here we have the exponent of 3
what if we have (2^6)(2^15) though, who really wants to multiply 2 that many times ? Well the rule says there's a short cut
And what would that be?
I can say (2^3) times (2^15) is equal to 2^18
Uh huh but wouldn't that be more difficult?
no, both ways are equivalent so either way can represent our number
2^3 and 2^15 can be said to be factors of 2^18
Uh huh.
In fact, 2^(any number from 0 to 18) can be said to be a factor of 2^18
Huh, not 5?
Because any number between 0 to 18 will add up to 18 given another factor
2^5 is a factor of 2^18 because there's 2^13, make sense?
Yes.
So if we had numbers c and d as exponents with base 2 what would we have as a product?
We'd have 2^(c+d)
Do you think you understand the rule now?
These rules may come in handy
But for this problem we only need focus on rule 1.
Do you follow?
Yes.
the common factors for this is ab^2(ab)
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