Question

Can someone show me step by step on how to solve quadratic equations?

Answer 1

Solve x^2 + 6x + 7 = 0

Answer 2

how do i start to solve this?

Answer 3

erm.?

Answer 4

7 and 0... ?

Answer 5

\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

Answer 6

shadow how would i plug in for my equation? What would be what in the equation shown?

Answer 7

Why does he have to combine like terms...

Answer 8

im confused on the like term part of what you said.

Answer 9

\[ax^2 + bx + c = 0\]

Answer 10

\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a } \]

Answer 11

\[x^2 + 6x + 7 = 0 \]

Answer 12

See the connection?

Answer 13

Okay, I see it there hold on ima try plug in from there!

Answer 14

kk

Answer 15

okay trying to insert the numbers i have and what you shown with the ax^2 +bx+c=0 but how would I plug into the other equation?

Answer 16

ax^2 + bx + c = 0 is an equation that assigns the numbers of your quadratic equation to a variable

For example, in your equation , b = 6

Answer 17

oh so i would forget the x part when plugging in?

Answer 18

Basically

Answer 19

okay i think i got it \[-6\pm \frac{\sqrt{6^2-(4)(1)(7)}}{2(1)}\]

Answer 20

yep

Answer 21

is that correct on set up?

Answer 22

\[-6\pm4\] ?

Answer 23

Input:

\[-6 \pm \frac{ \sqrt{6^2 -4(1)(7)} }{ 2(1) }\]

Simplify \[-6 \pm \frac{ \sqrt{36 - 28} }{ 2 }\]

Answer 24

\[\frac{ -6 \pm \sqrt{8} }{ 2 }\]

Answer 25

\[\frac{ -6 \pm 2\sqrt{2} }{ 2 }\]

Further simplify

\[-3 \pm \sqrt{2}\]

Answer 26

Remember that, that is two solutions

Answer 27

\[x = -3 + \sqrt{2}\]

and

\[x = -3 - \sqrt{2}\]

Remember that plus or minus sign

Answer 28

As you may have seen by now, there are plenty of ways in which you can solve quadratic equations. Using the quadratic formula is one of them. What are some of the others?
Completing the square, factoring, graphing and several more. Please narrow down your question by mentioning the method you want to learn.