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:D
it wont allow me to attach the pic in the main q haha
is this science mixed with math?
yes, applied math :)
I'm just going to guess for this, because I can't remember the laws at play. Well \(I_P\) is when the distance is \(d\). Then if the distance distance is \(3d\) uses the formula: \[ (3d)^2I_{MP} = (d)^2I_P \implies I_{MP} = \frac{d^2}{9d^2}I_p=\frac{I_p}{9} \]Add this to the already existing intensity and we have: \[ \frac{I_p}{9}+I_p = \frac{10}{9}I_p \]So I would think \(10/9\).
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that looks perfect! yeah `1 + 10/9` is the answer, thanks :)
I got \(1+1/9=10/9\) though
`10/9` is the answer, sorry
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