Question

The base length of a particular triangle is 8 meters more than twice its height. A
new triangle is formed by increasing the base by 10 meters and increasing the height by
5 meters. The area is 65 square meters more than the area of the original triangle. Find
the base length and height of the original triangle.

Answer 1

Can you show me your approach ??

Answer 2

I am confused on this problem.. I have tried to do it but I keep getting confused

Answer 3

let the base of triangle1 be "b" and height be "h" => b = 8+2h

A1 = b*h/2 = h*(h+4) (after simplification)

Can you try the same thing with triangle2 ??

Answer 4

I was thinking triangle 2 would be like , b + 10 and h + 5.

That last part of what you wrote is confusing to me.

Answer 5

i just found the area of the first triangle... A1=(8+2h)*h/2 = 2*(h+4)*h/2=(h+4)*h

Answer 6

for triangle2 A2 = (b+10)(h+5)/2 = (18+2h)*(h+5)/2 = (h+5)*(h+9)

Also A2 = A1 + 65

Answer 7

Hope that helps