Question

anyone can teach me about limt please ?

Answer 1

limits calculator

Answer 2

I think maybe @Directrix or @FortyTheRapper can. I'm sorry I can't.

Answer 3

what is the limit? I could try to help

Answer 4

This is your limit right? \[\lim_{x \rightarrow 3} \frac{ x-9 }{ x-3 }\]

Answer 5

according my knowledge there 5 trick to slove limits beacuse some limit give you an 0 and that time it isnt full answer

Answer 6

but i dont know to doing it

Answer 7

sorry just checked that's wrong... have another idea

Answer 8

well when limits = 0 its wrong , we need to use other trick

Answer 9

i can answer , but when its = 0 what i should do to fix it

Answer 10

I guess we can express it like this as a product of two limits instead of 1

\[\lim_{x \rightarrow 3}(x-9) * \lim_{x \rightarrow 3} \frac{ 1 }{ (x-3) }\]

Answer 11

let's choose a number that's close to 3

Answer 12

say

\[1/(2.999-3) = ~ -1.0*10^{3}\]

Answer 13

if you notice as you get closer to 3. the numbers get extremely large and negative

Answer 14

I guess we can express it like this as a product of two limits instead of 1

\[\lim_{x \rightarrow 3}(x-9) * \lim_{x \rightarrow 3} \frac{ 1 }{ (x-3) }\] = -infinity

Answer 15

what we did to get close to 3 , are we just mines number 3 , or plus.. i didnt understand
what we did

Answer 16

but that's as the limit approaches from the right. the full limit doesn't exist

Answer 17

I guess we can express it like this as a product of two limits instead of 1

\[\lim_{x \rightarrow 3^+}(x-9) * \lim_{x \rightarrow^+ 3} \frac{ 1 }{ (x-3) }\] = -infinity

so I chose a number close to three from the right

Answer 18

@robtobey

Answer 19

so we choose number 4?

Answer 20

whats the equation ?

Answer 21

are you sure the question does not have
\(x^2-9\)
in the numerator?

Answer 22

theres an easier way to solve this.. o.o

Answer 23

i want to know the tricks how to slove limits in general not this only

Answer 24

well if you plug in the number and the top is for example. 0/0 then theres sumthun wrong then ull have to split the equation one+ and - sumtimes gives u dne but it depends

Answer 25

depends on what?

Answer 26

First: are y ou certain that the original problem doesn't involve (x^2-9) / (x- 3) ?

Secondly, your question is much too broad. There are numerous "tricks" for finding limits in different situations; not every "trick" applies to every problem.
so, find and post problems that are at just about the level of difficulty that you are comfortable with, and practice those problems. Then move on to harder ones.

Answer 27

well if ur answer is 0/0 then ur left with options 1. conjugate 2. u can graph it on ur calculator.

Answer 28

The limit \[
\lim_{x\to 3}\frac{x-9}{x-3}
\]doesn't exist because it approaches different infinities from both sides.