Totally Confused regarding Rational Root Theorem + Descartes Rule of Signs!
What are the possible rational zeros of f(x) = 2x3 − 15x2 + 9x + 22?
± 1, ± 2 ± 1, ± 2, ± 11, ± 22 ± 1, ± 1 over 2, ± 2, ± 11 over 2, ± 11, ± 22 ± 1, ± 1 over 2, ± 1 over 11, ± 1 over 22, ± 2, ± 2 over 11
@Directrix
@phi
Can you help me?
@ikram002p
@KendrickLamar2014
@Loser66 @johnweldon1993 @uri @jhonyy9
:I
I was expecting you to help me out via communication
wait what
I'm lost
I know about coefficients
But i'm wondering how you would apply this to all problems.
Like I said, I dont want answers :P
I wanna learn
^^^
Can you chime in Xavier?
?
I just still dont understand
Look at the youtube link than
w/e
thanks for posting links atleast
_-_
Can you factor the polynomial?
Yes.... i think
How does factoring have to do with this?
Oml
Please help me out :(.
Try factoring 2x^3 -15x^2 +9x
What do you mean by factoring... like synthetic division?
Factoring (called "Factorising" in the UK) is the process of finding the factors: Factoring: Finding what to multiply together to get an expression. It is like "splitting" an expression into a multiplication of simpler expressions.
What i'm wondering is how to solve the problem, I don't know how factoring has to do with it though.
You know x is a factor, how else can you break it apart bit by bit?
2x^2 * 2x^1?
?
After you factor the problem, that is find each component, the zeroes will be easy to see. You want to represent it so that every term is fully factored
Can't I just use the coefficient of the first and last term? Find the factors of both of them (22=1,2,11,22) and do them on top of the first term (2=1,2)?
Atleast that's what i'm thinking?
No, look x( x ( 2x-15) + 9 ) +22 is something you can get if you just think about the components of the function
So what would you use that for?
Use it to break it down further... The idea is to get something resembling a(x+b) + c(x+d) + C so when x=-d that is root of the function or an x value where the whole function become zero
b = d in this case
So factors of 22/factors of 2?
22 is just a constant outside nothing to do our variable
Wait, I think I knda get it now without doing what you are asking... please let me know whether its right or not. Factors of 2: 1,2 Factors of 22: 1,2,11,22 Factors of 22/2 1/1 = 1, 1/2, 2/1=2, 2/2=1 (we have that), 11/1=11,11/2, 22/1 22/1=11(we already have that. So the answer would be C?
@daniel.ohearn1
@uri
no-one?
:(
Looking at P(-x)
How many times does the polynomial change signs?
2
looks like one to me
2(-x)^3 is negative -15(-x)^2 is negative 9(-x) is negative and 22 is positive
HI!!
What are the possible rational zeros of \( f(x) = 2x^3 − 15x^2 + 9x + 22\)
3
take all fractions where the numerator goes in to 22 evenly (so 1,2,11,22) and the denominator goes in to 2 evenly (so 1 and 2) don't forget the \(\pm\) since they could be positive or negative
the list is fairly long, but not too long if you divide by 1 you get the whole number, so a start is \[\pm1,\pm2,\pm11,\pm22\]
then divide all those by 2 and you are done
Desc Rule of Signs says that if there are only 2 sign changes there can only be one or two negative roots right??
so factors of 22/factors of 2
this questions seems to only ask for the rational root theorem descartes rule of sign tells you something else, namely how many possible positive and negative roots there are
okay, can you help on a problem that talks about descartes?
sure why not?
What are the possible numbers of positive real, negative real, and complex zeros of f(x) = 6x3 − 3x2 + 5x + 9? Positive Real: 1 Negative Real: 0 Complex: 2 Positive Real: 1 Negative Real: 2 or 0 Complex: 2 or 0 Positive Real: 2 or 0 Negative Real: 1 Complex: 2 or 0 Positive Real: 2 or 0 Negative Real: 2 or 0 Complex: 1
Yes, but acknowledging only descartes narrows it down big time
Looking at your poss. answers
what really narrows it down is finding them all this muck is an artifact of history, not something useful today
not true, if you want to build something with this sort of shape
or if you want to travel across it
can i get help on the problem either way :)?
\[f(x) = 6x^3 − 3x^2 + 5x + 9\] the coefficients have two changes in sign from \(+6\) to \(-3\) and fron \(-3\) to \(+5\) that means there are either 2 or no positive zeros (you count down by twos)
I think its the 3rd one
now you have to consider \(f(-x)\) which in this case is \[f(-x)=-6x^2-3x^2-5x+9\] how many changes in sign here?
1?
right so there must be a negative root since you count down by twos, and you cant have minus one negative roots !
so 1 negative root?
definitely one
no more, no less
Then the complex would be 2
could be 2 or could be none, depending on whether there are 2 or no positive ones both are possible, 2 positive, no complex or 2 complex, no positive
ok
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