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A carnot engine having efficiency 40% used as a refrigerator. If work done by compressor of gas is 100J.Find heat absorbed from the body having lower temperature.
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I got the ans as 150J. And it is wrong
@ganeshie8
@QueenFromADayOfRace @nubeer
http://www.ohio.edu/people/piccard/phys202/carnot/carnot.html if that link is correct then you are looking at \(0.4 = \dfrac{Q_e}{100 - Q_e}\) scroll down to fridge
@ganeshie8
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3rd Last post i made
Further beta is q2/w Q2 is heat absorbed from the sink W is work done on the fridge by external source
Beta=3/2 And if i substitute it into Beta=q2/w
We get q2=150J
@irishboy123 pls help
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@pawanyadav
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