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can someone please 1. Verify (1/cosx+1)+(1/cosx-1) = -2cscxcotx
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[1 / (1 - cosx)] + [1 / (1 + cosx)] = 2csc²x Working with the left side: [1 / (1 - cosx)] + [1 / (1 + cosx)] Give common denominators: [(1 + cosx) / (1 - cosx)(1 + cosx)] + [ (1 - cosx) / (1 - cosx)(1 + cosx)] Add these together: [1 + cosx + 1 - cosx] / [(1 - cosx)(1 + cosx)] SImplify the numerator and expand in the denominator: 2 / (1 - cos²x) Use the Pythagorean Identity: 2 / sin²x Thus: 2csc²x
it is not negative
that's how the question is
what are you looking for
the anwser how to get the anwser
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yes anthony you are right sure - nice work
thanx
thank you anthony.
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