Question

A manufacturer produces soda cans and a quality control worker randomly selects two cans from the assembly line for testing. Past statistics show that 14% of the cans are defective. What is the probability that the two selected cans are defective if the quality control worker selects the two cans from a batch of 50 cans?

P(Both defective) = 7/50
P(Both defective) = 49/2500
P(Both defective) = 3/175
P(Both defective) = 7/25

Answer 1

Past statistics show that 14% of the cans are defective.
Two cans are selected from a batch of 50 cans.
What is 14% of 50?

Answer 2

@lydiasantos

Answer 3

THanks Aveline, in that case its 7/50 ??

Answer 4

because 14% of 50 is 7

Answer 5

right?

Answer 6

Actually 7/50 is the chance of selecting one defective can.
If we want to find the chance of selecting two defective cans, we need to multiply. \[\frac{ 7 }{ 50 }\times \frac{ 7 }{ 50 }\]

Answer 7

oh okay, so then its 49/2500 ??

Answer 8

Yes ^^

Answer 9

cool thanks