Question

tiny question regarding this log problem

Answer 1

\[\log_4x+\log_44=5\log_42\]

Answer 2

Any idea how you are going to solve this?

Answer 3

so I've gotten to this point:
\[\log_44x4=5\log_42\]

Answer 4

oops 4x*

Answer 5

Okay so we have..

\(\log_{4}(4x) = 5 \log_{4}2\)

Answer 6

right, so then would you cancel the logs?

Answer 7

We are going to use one more property of log...

\(a \log_{b} x = \log_{b} x^{a}\)

Answer 8

So our RHS will become?

Answer 9

RHS?

Answer 10

Right hand side... i.e. \(5\log_{4} 2\)

Answer 11

oh okay \[\log_42^5\]?

Answer 12

Great!

Answer 13

Now you can cancel log... :)

So you will get...

\(4x = 2^5\)

Answer 14

then just solve?

Answer 15

Yeps :)

Answer 16

x=8, thank you soo much!

Answer 17

Glad to be of help :)