Someone please help!
Find the integral of sec20tan20do using u substitution
@mathmale
the derivative of what function is sec x tan x ... ?
Secx
@mathmale sorry had to eat
Good. Hope you're full now. sec 2x*tan 2x *2 is the derivative of what function?
Be sure to review the Chain Rule if need be.
I have no idea :/
Tanx? I don't know
@zepdrix confused here
Sec^2
but what's your argument? sec x can't stand alone. Must have an argument.
The derivative of what function is sec 2x tan 2x *2?
Ugh
2secx I really don't know :(
the derivative with respect to x of sec 2x) is sec 2x tan 2x * 2. But you were asked to find the integral of only sec 2x tan 2x (no 2!). What function, when differentiated with respect to x, produces the derivative sec 2x tan 2x * 2?
Hold that for a moment (it's correct, but I wanted to ask you to try something else). Differentiate sec x tan x. Next, differentiate sec 2x tan 2x. Are the results the same or different? You must follow the Chain Rule in the 2nd case.
and the reason for that is that 2x is itself a separate function.
Just give me a second
They aren't the same
Right, they're not. Look: sec x is a function. But so is 2x. Thus, if you want to find the derivative wrt x of (sec 2x)^2, you get sec 2x tan 2x times the derivative of 2x (which happens to be 2). OK with this so far?
Yes
In taking the derivative of 2x, you have successfully applied the Chain Rule. OK: you wanna do substitution? Fine. Let u=2x. Find du/dx. du/dx=?
Du/Dx=2
Right. You want to integrate sec 2x tan 2x dx. Since u=2x, and du/dx=2, solve the 2nd equztion for dx now, please. dx=?
1/2du=dx
Right. So, instead of integrating sec 2x tan 2x dx, you're gonna integrate dy= sec u tan u (du/2).
Gotta get rid of that /2. So, Move that (1/2) to in front of sec u tan u du.
Okay and that makes sense
so now you are integrating (1/2)[sec u tan u du]. What's the integral? Don't forget that (1/2).
Remember you have already successfully integrated sec x tan x dx. SAME THING.
1/2secu
Plus C. ;)
Oh yeah!
And put parentheses around that doggone 1/2, please.
Okay!
So your final answer is ... ? Be careful; you did not start with the variable u; you began with 2x. So, your final answer is...?
(1/2)sec(2x)
Plus what?
C!
Kool as all get out.
Forgive my pestering you, but we want you to get a very high grade in calculus, don't we?
Yes
go for it! Take care, over and out, bye.
Thank you! :)
:)
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