Question

For z1=[(1-i)/(1+i√3)]^(1/6)
z2=[(1-i)/(√3+i)]^(1/6)
z3=[(1+i)/(√3-1)]^(1/6)
Which of the following holds?
A).summation of |z|^2=3/2
B).summation of |z1|^3+|z2|^3=|z^3|^-6
C).|z1|^4+|z2|^4=|z3|^-8
D).|z1|^4+|z2|^4=|z3|^8

Answer 1

@ganeshie8

Answer 2

|Z3|^-6 in second option (rhs)

Answer 3

@ilovepuppieslol

Answer 4

@loser66

Answer 5

I can't read it . Can you take a snapshot?

Answer 6

I use os on mobile..

Answer 7

@snowsurf

Answer 8

This looks like a complex analysis problem. I'm not sure about this one.

Answer 9

@hartnn

Answer 10

all the z's have magnitude 1/sqrt 2
isn't it ?

also, whats the denominator of z3 ?

Answer 11

i mean magnitude as
\((\dfrac{1}{\sqrt 2})^{\dfrac{1}{6}}\)

Answer 12

Ty..