What is the value of the ones digit in the solution to ...
\[2^{326}\]
How would I solve this??
The answer is 4...
The only addition involved here is addition of the exponents. \[2^{326}=2^{300}2^{20}2^6\]
I see
I suggest you try to find a relationship that correctly predicts the final digit of any given positive power of 2. For example, if n=1, 2^n=2 If n=2, 2^n=4 If n=3, 2^n=8 2^4=16 2^5=32 2^6=64 .... 2^10 = 1024 According to this experiment, the final digit is 4 when n=2, 6, 10, 14, 18, and so on Take this idea and run with it. Can you predict what the final digit will be if n=326?
hmm I'm kind of lost here. I get your experiment but I don't know how to apply to the problem
If I plug 326 for my n, I get 1.36....
2^326=1.36E98
So basically, finding the first digit of 2^326 is to find 2^326 mod 10. Do you know the laws of modular arithmetic?
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