A kicker kicks a football toward the opponent's goal line during a game. The ball begins its flight with an initial velocity of 90 feet per second when it is kicked at a height of 2 feet by the kicker. To the nearest foot, what maximum height will the ball reach?
Use the function h(t)=-16t^2+70t+2

Question

A kicker kicks a football toward the opponent's goal line during a game. The ball begins its flight with an initial velocity of 90 feet per second when it is kicked at a height of 2 feet by the kicker. To the nearest foot, what maximum height will the ball reach? 
Use the function h(t)=-16t^2+70t+2

maddy1251 · Answer

I think I can help ya out. :D

maddy1251 · Answer

I made an oops, I think...
h '(t) = v(t) = -32t + 90 

When ball reaches maximum height, velocity is zero 

-32t + 90 = 0 

32 t = 90 

t = 90 /32 

= 45 /16 

substitute t = 45/16 in h(t) 

h(45/16) = -16(45/16)^2 + 90(45/16) + 2 

= 128.56 ft

I think this is the correct answer now?

anonymous · Answer

thanks but i already answered it i got 159 >.<