Question

I just need someone to explain this to me


Resistance is the ability of an object to slow down current. The higher the resistance the less current there will be in a circuit. The unit of resistance is the Ohm. Notice that our lightbulbs have a resistance of 10.00 Ohms. Knowing this how do you think the lightbulbs in the circuit contribute to the differences that we see in current and voltage for these circuits?

Thank you!

Answer 1

Use Ohm's Law: \(\sf V=I \times R\)
where V is the voltage, I is the current and R is the resistance.

You see that as resistance increases, the potential (voltage) also increases because they are directly proportional. Also, as mentioned from the question itself, as the resistance increases, the current decreases since they are inversely proportional to each other.

Now in your problem, the light bulbs have resistances that affect the voltage and the current of the circuit. It actually depends if they are connected in parallel or in series but anyways, I'll just assume that it only focuses on the effect of the resistance on the circuit. Just follow Ohm's Law that I mentioned above and you'll be good.

Answer 2

It's actually both series and parallel currents that we're studying so I think it believes both of them? I know that parallel circuits have less resistant on the current than series circuits do.

Is that what they're asking me to state?

Answer 3

yes you're right. Probably that is what your the question is asking. To make sure, I think it is better to explain the relationship of the resistance to the voltage and current , then explain the resistance in both parallel and in series circuit.

Answer 4

Oh okay thank you! That one just wasn't making sense to me!

Answer 5

np :P why don't you ask your teacher tho?

Answer 6

I go to online school and my teacher is out of the office today so mostly it's me figuring things out

Answer 7

oh okay, goodluck (:

Answer 8

Thank You!