Question

4arcsinx-4pi= 2arcsin5pi. find exact value. can someone show me all the steps?

Answer 1

not sure i can read it \[4\sin^{-1}(x)-4\pi=2\sin^{-1}(5\pi)\]?

Answer 2

that can't be right, must be something else

Answer 3

the first half is correct the 2nd half is 2arcsin x -5pi

Answer 4

I'm sorry i typed it wrong

Answer 5

isolate the arcisne first
like solving \[4x-4\pi=2x-5\pi\] for \(x\)

Answer 6

clear or no?

Answer 7

yes I'm trying it

Answer 8

i got -pi/2

Answer 9

yes

Answer 10

so you have \[\sin^{-1}(x)=-\frac{\pi}{2}\]

Answer 11

making \[x=\sin(-\frac{\pi}{2})\]

Answer 12

that wasn't one of the answer choices

Answer 13

would it be -1/2?

Answer 14

noi it is not -1/2

Answer 15

look on the unit circle to find \[\sin(-\frac{\pi}{2})\]

Answer 16

oh okay i see it now so it would be -1

Answer 17

yes

Answer 18

thank you!