help me.
Questions here.
The area of a circle is given by \[A =\pi r^2\] and circumference is \[C=2 \pi r\] They both have a radius r in common. You know the area so what you can do solve for r from the equation for area of circle, \[\sqrt{\frac{ A }{ \pi }}=r\] Take that and plug into the circumference equation \[C=2 \pi \sqrt{\frac{ A }{ \pi }}\] With this equation you can find the circumference of a circle when given the area of a circle.
ok.
From the area of the circle, get the radius of the circle. A = π * r² 81π = π * r² r = ? @TylerMckinney16
hey sorry i was asleep lol.
@Directrix
@Directrix @nincompoop @Photon336
@rebeccaxhawaii
C=2*pi*r as you can see you don't have the value of "r" right now.. so try finding that first.. you can do that by using the method Directrix told.. can you find the value of r now?
could u show me how.
like how i set it up
From the area of the circle, get the radius of the circle. A = π * r² 81π = π * r² r = ?
508.94
?
no. O.o how did you got that.. can you show how u did it?
Wait sorry i did something wrong ok i did what u said and got .31.9
the pi would cancel out on both sides .. do you agree on that?
Yeah.
so you are left with 81 =r^2 right?
yeah
take square root of 81.. what do u get?
9 is the square root of 81 right.
yes
you should check where you went wrong in calculating ok? so r=9
ok and the answer is r=9?
its not the answer.. you need r to find the circumference.. you know the formula for it?
no
C=2πr with this formula you can find it.. now you have the value of r.. plug it in this equation..
2.39 ?
no. can you show me how you are doing?
r = C/2π bC = 11.9 metres so the radius is 11.9/2π That is 1.9 m to the nearest tenth.
right?
no.. you have to find the find the value of C. C = 2*pi*r you have the value of r. plug it in. C= 2 *pi* 9
56.52? 9*3.14*2=56.52
yes.. but read the question carefully.. it says leave ur answer in terms of pi. so dont put the value of pi.. but u did it right anyway
So i just put pi instead the value? 9*pi*2=56.52?
C=2*pi*9 C=18*pi. just leave it like this.
ok cool.
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