Question

Can someone help me with this problem? I don't get it. (In attachment below)

Answer 1

specific postings helps

Answer 2

It's in the attachment

Answer 3

@Directrix @jabez177 @jdoe0001 @Luigi0210 @Mehek14 @silveralchemist09

Answer 4

@welshfella

Answer 5

hold the mayo

Answer 6

?

Answer 7

one sec

Answer 8

ok

Answer 9

you know how to convert a mixed fraction to "improper" one right?

Answer 10

Yeah

Answer 11

k

Answer 12

\(\bf \left( 6\frac{4}{5}x-5\frac{3}{4} \right)\ - \
\left( 1\frac{1}{3}x-2.5 \right)
\\ \quad \\

\left( {\color{brown}{ \cfrac{34}{5} }}x-{\color{brown}{ \cfrac{23}{4}}} \right)\ - \
\left( {\color{brown}{ \cfrac{4}{3}}}x-\cfrac{\cancel{25}}{\cancel{10}} \right)\implies
\left( {\color{brown}{ \cfrac{34}{5} }}x-{\color{brown}{ \cfrac{23}{4}}} \right)\ - \
\left( {\color{brown}{ \cfrac{4}{3}}}x-\cfrac{5}{2} \right)
\\ \quad \\
\cfrac{34}{5}x-\cfrac{23}{4}-\cfrac{4}{3}x+\cfrac{5}{2}\implies
\cfrac{34}{5}x-\cfrac{4}{3}x-\cfrac{23}{4}+\cfrac{5}{2}\)

there, just get the LCd and add them up

Answer 13

5, 3, 4, 2
the LCD is most likely 5*3*4, since that contains 2 as well