Question

If the actual frictional force is equal to 1 lb., then how much effort (force) would be required to drag a 90 lb. box up the plane?

10+ lb.
10- lb.
9+ lb.
9- lb.

Answer 1

am i really??

Answer 2

tbh i guessed im not so sure..

Answer 3

if friction is 1 lb ,then you are dragging 90+1=91 lb
so force required is more than 10 lb.
Earlier my conception was wrong.

Answer 4

\[91 \times \frac{ 1 }{ 9 }=?\]

Answer 5

so positive 10 is the answer correct?

Answer 6

or is it negative 10?