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\[\log_x4=\frac{ 2 }{ 3 }\]
so I can get to the point of making it: \[x^\frac{ 2 }{ 3 }=4\] but I'm kind of confused what happens after that
hint... \[x^{\frac{1}{2}2} = x\]
And its ok to raise both sides of the equation to same power.
so 4 would turn into 16?
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yep, if you square it, but you don't want to square it.
how do I raise stuff to the 1/2 then?
nope, need to raise it to a power to change \[x^{2/3} ---> x\]
I meant 2/3...oops
3/2
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\[4^{3/2} = \sqrt{4^3}\]
you can also notice \[2*2=4\] to help simplify
oh I see so...64?
square rooted would be 8
yep.
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so then the final answer would be 8
\[((2^2)^{1/2})^3=2^3=8\]
yep, x=8
I see, that's not too bad :)
:)
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thank you
np
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