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Mathematics 22 Online
OpenStudy (anonymous):

okay guys, this is my call for help. I'm doing magnitude and direction of vectors and I need help. Please help! specific question below. Also, I need understanding, not just an answer please.

OpenStudy (mathmale):

Please, post your question immediately, so that potential helpers don't have to ask you for it.

OpenStudy (anonymous):

What is the magnitude and direction of the resultant of a 105-newton force along the x-axis and a 110-newton force at an angle of 50 degrees to one another?

OpenStudy (anonymous):

sorry @mathmale here it is

OpenStudy (anonymous):

@mathmale can you help?

OpenStudy (anonymous):

@iGreen can you help me?

OpenStudy (mathmale):

"What is the magnitude and direction of the resultant of a 105-newton force along the x-axis and a 110-newton force at an angle of 50 degrees to one another?" Would you please draw this situation. Use the Draw utility, below.

OpenStudy (mathmale):

|dw:1459447221653:dw|

OpenStudy (anonymous):

|dw:1459447225684:dw|

OpenStudy (anonymous):

|dw:1459447434212:dw|

OpenStudy (anonymous):

actually, it's 50 degrees, so the second one is correct, my bad

OpenStudy (mathmale):

"What is the magnitude and direction of the resultant of a 105-newton force along the x-axis and a 110-newton force at an angle of 50 degrees to one another?" You'll need to find the x-components of these two vectors, and then, separately, the y-components. Know how to do that? You'll need to use trig in connection with the 110N vectpr/

OpenStudy (anonymous):

yes, is the horizontal component for the 105N vector just 105, and the vertical component 0?

OpenStudy (mathmale):

Very good. Now, what are the comps for the 110 N force?

OpenStudy (anonymous):

horizontal is 70.7 and vertical is 84.3

OpenStudy (anonymous):

okay so now what?@mathmale

OpenStudy (anonymous):

@mathmale

OpenStudy (mathmale):

Add the horizontal comps together. Show your work. What result do you obtain? Next, add the vertical comps together. Your result?

OpenStudy (anonymous):

horizontal = 175.7 anf vertical = 84.3

OpenStudy (mathmale):

very good. Now, treat those horiz and vert comps like you would the legs of a right triangle. Apply Pythagorea's Theorem to find the magnitude of the "resultant vector" What is this magnitude? You also need to figure out what angle this resultant vector makes with the x-axis.

OpenStudy (anonymous):

the magnitude of the resultant vector is 194.9, how do I find the direction?

OpenStudy (mathmale):

use the inverse tangent function. Specifically, find\[\angle=\tan ^{-1}\frac{ vertical~comp }{ horiz~comp }\]

OpenStudy (anonymous):

25.6!

OpenStudy (anonymous):

how does this process change when there are three vectors?

OpenStudy (mathmale):

Haven't done it myself, but that result looks appropriate and reasonable. Process is the same with more than 2 vectors. Find the sum of the horiz comps. Find the sum of the vert. comps. Find the hypotenuse thru Pyth Thm. Use the inverse tan functio to find the angle.

OpenStudy (anonymous):

perfect. thank you sooooo much!!!

OpenStudy (mathmale):

My pleasure. Seems as tho' you really know your stuff! Take care. Over and out.

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