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Mathematics 22 Online
Hayhayz (hayhayz):

http://prntscr.com/amimft @imqwerty

imqwerty (imqwerty):

here the x coordinate of the points represent "n" and the y coordinates represent "\(a_n\)" we will solve this question by trying out the options by "trying out the options" i meant that we will select any of the 3 given points and substitute the value of n ( the x coordinate) into the options the option which gives the correct value of corresponding \(a_n\) to that "n" is correct it may happen that 2 options give correct value of "\(a_n\)" for a particular "n" in that case try another "n" ( i mean another point :) )

Hayhayz (hayhayz):

Uhh ok tell me how to start it lol im slow on this one

imqwerty (imqwerty):

okay well the point (1,3) looks cute so we will start off with it so the correct option will give "\(a_n=3\)" when we put "\(n=1\)" in it \(\color{blue}{option~1}\) \(a_n=3 \large \left(\frac{1}{5}\right)^{n-1}\) putting n=1 \(a_n=3 \large \left(\frac{1}{5}\right)^{1-1}\) \(a_n=3 \large \left(1\right)\) \(a_n=3\) \(\color{blue}{option~2}\) \(a_n=3(-5)^{n-1}\) \(a_n=3(-5)^{1-1}\) \(a_n=3(1)\) \(a_n=3\) \(\color{blue}{option~3}\) \(a_n=0.3(5)^{n-1}\) \(a_n=0.3(5)^{1-1}\) \(a_n=0.3(1)\) \(a_n=0.3\) similarly you can try out the 4th option now here we see that options 1 and 2 are giving correct value for \(a_n\) so they might be correct but option 3 is giving wrong value of \(a_n\) so it is wrong now we need to find which one of options1 or 2 is correct so wee will take another point (for example (2,0.6)) and then check

Hayhayz (hayhayz):

How did you get the 3(1) each time for the first 2? Like where did the -5 go?

imqwerty (imqwerty):

anything raised to the power "0" is "1" \(\color{red}{except~this~case- 0^0}\) so like in 1st equation we had this- \(a_n=3 \large \left(\frac{1}{5}\right)^{1-1}\) \(a_n=3 \large \left(\frac{1}{5}\right)^{0}\) \(a_n=3 \large \left(1\right)\)

Hayhayz (hayhayz):

Yeaa uh I can't process this one so ima guess the second option is right xD

imqwerty (imqwerty):

noo thats wrong cx

Hayhayz (hayhayz):

1st option

imqwerty (imqwerty):

e.e thats correct

Hayhayz (hayhayz):

xD

imqwerty (imqwerty):

:)

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