What is the vertex of the parabola? Assume p > 0. (0, p) (0, -p) (0, 0) (p, 0) (-p, 0)
give a ring to Mr P, he's greater than 0, so he's home, he'd know where the vertex is at
I like your response :). Medaled ;).
=)
sorry im confused
I mean, we don't have a picture or equation for the posting so, unless I use my crystal ball, which I don't have, sadly or use my clairvoyance powers, which I sadly lack then we're a bit on the lurch
all i got was the information i gave in my first question so im as confused as you are man
hmmm I just noticed the "edited" version of the posting hmmm I see the choices
hahah yeah
hmmmm that's very ambiguous for one choices A and D both have positive "p" so both are valid for that reason alone
is p defined anywhere? is p distance between the focus and the vertex?
the only info i got was the info in the vary first question
but in your class are you using p to mean anything specifically ?
for some reason I think you are using that p is the distance between the focus and vertex (or the directrix and vertex which is equivalent distance)
this is an online class so i really dont have any idea what is happening half the time
ok
PART A T he equation for a parabola with directrix y = –p and focus (0, p) is: https://hanwingspanps.owschools.com/media/g_alg02_ccss_2015/8/equation_parabola.gif PART B A parabola can be translated so that its vertex is not at the origin or on an axis. (Remember that a translation moves or maps every point the same distance and direction.) The equation for a parabola with directrix y = k – p and focus (h, k + p) is: https://hanwingspanps.owschools.com/media/g_alg02_ccss_2015/8/equation_parabola_directrix.gif The value of k changes the placement of the parabola. Assume that p > 0. There are 3 cases to consider: 1.k > 0 2.k = 0 3.k < 0 PART C The zeros of the polynomial are the same as the roots of the equation https://hanwingspanps.owschools.com/media/g_alg02_ccss_2015/8/roots_of_equation.gif
@freckles i have no idea if this will help but this is the info they gave me
that does help
we are given the directrix is y=-p and the focus is (0,p) the vertex is suppose to lay right smack between this two items.
|dw:1459467530022:dw| what ordered pair lays right smack between the ordered pair (0,p) and the point (0,-p) (this point falls directly underneath the focus and lays on the directrix)
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