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Mathematics 5 Online
OpenStudy (anonymous):

Help with geometry?

OpenStudy (melody323):

What do you need help with?

OpenStudy (anonymous):

Just a few simple questions! I think I know the answers, but I'm really struggling :c

OpenStudy (anonymous):

@Melody323

DivineSolar (divinesolar):

Depends what kind of geometry, translations, reflections, rotations?

OpenStudy (melody323):

Ok what are they?

OpenStudy (anonymous):

it's based on determining posulates :)

OpenStudy (anonymous):

like, they give visuals and information but I'm more caught in a mind bump because I'm torn between two answers, you know?

OpenStudy (anonymous):

I will medal and fan - I just would really like to know :)

DivineSolar (divinesolar):

A statement, also known as an axiom, which is taken to be true without proof. This is a postulate so this should not be too hard. Questions and answers?

OpenStudy (anonymous):

The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel: A quadrilateral ABCD is shown with the opposite sides AB and DC shown parallel and equal A student wrote the following sentences to prove that quadrilateral ABCD is a parallelogram: Side AB is parallel to side DC so the alternate interior angles, angle ABD and angle BDC, are congruent. Side AB is equal to side DC and DB is the side common to triangles ABD and BCD. Therefore, the triangles ABD and CDB are congruent by _______________. By CPCTC, angles DBC and ADB are congruent and sides AD and BC are congruent. Angle DBC and angle ADB form a pair of alternate interior angles. Therefore, AD is congruent and parallel to BC. Quadrilateral ABCD is a parallelogram because its opposite sides are equal and parallel. Which phrase best completes the student's proof? AAS Postulate HL Postulate SAS Postulate SSS Postulate

DivineSolar (divinesolar):

Proofs is what you meant, not postulates :).

OpenStudy (anonymous):

Here is the figure :)

OpenStudy (anonymous):

oh, whoops! yes proof :') sorry, terminology mix up

DivineSolar (divinesolar):

Side AB is parallel to side DC . so the alternate interior angles, angle ABD and angle BDC are congruent. . Side AB is equal to side DC . and DB is the side common to triangles ABD and BCD. Therefore what?

OpenStudy (anonymous):

I am leaning towards SAS posulate

DivineSolar (divinesolar):

Correct.

OpenStudy (anonymous):

It's congruent, yes?

DivineSolar (divinesolar):

Yes.

OpenStudy (anonymous):

okay, thank you so much! would you mind helping me out with one more?

DivineSolar (divinesolar):

Sure. Lets see it.

OpenStudy (anonymous):

Maria drew two parallel lines KL and MN intersected by a transversal PQ, as shown below: Two parallel lines KL and MN with PQ as a transversal intersecting KL at point R and MN at point S. Angle KRS is shown congruent to angle MSQ. Which theorem could Maria use to show the measure of angle KRQ is equal to the measure of angle PSN? Alternate Exterior Angles Theorem Alternate Interior Angles Theorem Same-Side Interior Angles Theorem Vertical Angles Theorem

OpenStudy (anonymous):

here is the lines :)

DivineSolar (divinesolar):

Hold on, I am thinking about this....Might take me 5-10 minutes, If i cannot figure it out then, I will have you tag someone else okay? ^-^

OpenStudy (anonymous):

No problem! thank you so much :)

DivineSolar (divinesolar):

Do you know what each of those stand for?

OpenStudy (mathstudent55):

Notice the position of the angles.

DivineSolar (divinesolar):

The Alternate Exterior Angles Theorem states that, when two parallel lines are cut by a transversal, the resulting alternate exterior angles are congruent.

DivineSolar (divinesolar):

@mathstudent55 Hiya!

OpenStudy (mathstudent55):

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