Question

cccccccc.

Answer 1

@imqwerty

Answer 2

what does the question even mean....??????

Answer 3

this is the first type of question am doing in the assignment....didn't even do questions like that in the exercise...

Answer 4

okay i'll give some hint on how to start solving the question and then you continue

Answer 5

ye only gimme hints...ill do the rest of the question......

Answer 6

:")

Answer 7

bby whats grillin??

Answer 8

well here you cannot use calculator to find the value of \(\large log_{10}35\)

well lets say that the required value is "x"
so
\(\large log_{10}35=x\)

we need to find "x"

well we know that if
\(\large log_{10}35=x\)
then
\(10^x=35\)

we also know that \(10^1<35<10^2\)
we can also say that \(10^1<10^x<10^2\)

so "x" must lie between 1 and 2
so x must be like this-> x="1.sumthin"

now we need to guess that something

Answer 9

1.5?

Answer 10

not that 31.62...

Answer 11

yes 31.62 is close to 35
so x must be close to 1.5

can you check using calculator tho?

Answer 12

i can???idk

Answer 13

oh i get it the most decimals i add to the power the closer i get to the real number right?

Answer 14

yeah :)

Answer 15

1.55 lands right on the 35 for me.

Answer 16

so this question is solved =]

Answer 17

marry me righ NOW!!!

Answer 18

let's do a court marriage...

Answer 19

omg XD april's fool??

Answer 20

yeah!!! XD

Answer 21

thanks love

Answer 22

X'D np

Answer 23

see you in the next trouble...

Answer 24

i need to leave rn tho x~x