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Mathematics 5 Online
OpenStudy (mathmath333):

Probability question Coach has one tennis scholarship left...

OpenStudy (mathmath333):

OpenStudy (mathmath333):

|dw:1459653798803:dw|

OpenStudy (zarkon):

Do you know what the best strategy is?

OpenStudy (zarkon):

don't pick the first boy. then pick the next boy that is taller than the first.

OpenStudy (knov):

does 'one at a time' mean they exist the house at the same time ? kind of confused.

OpenStudy (zarkon):

no. it means that they come out one after another

OpenStudy (knov):

I see. So you assume that the best strategy is to choose not first one but second one without having look at the rest ?

OpenStudy (zarkon):

no. Don't pick the first guy...then pick the first kid that comes out (after the first) that is taller then the original guy

OpenStudy (zarkon):

the next tallest might not be the second boy

OpenStudy (knov):

But the first one can be the tallest one ?

OpenStudy (zarkon):

correct...then you end up picking the last one out of the house

OpenStudy (knov):

can he choose second one after seeing the 3rd and 4th one ?

OpenStudy (zarkon):

no

OpenStudy (zarkon):

he only has the option to choose a boy right when they come out of the house

OpenStudy (zarkon):

this is related to the Secretary Problem https://en.wikipedia.org/wiki/Secretary_problem

OpenStudy (zarkon):

they even give the probability \[\Large\frac{r-1}{n} \sum_{i=r}^{n} \frac{1}{i-1}\] in this case \(r=2\) and \(n=4\)

OpenStudy (knov):

So always to avoid the first choose.

OpenStudy (zarkon):

unless you have only one or two total choices

OpenStudy (knov):

yeah, that's for sure.

OpenStudy (knov):

here r equals 2 ?

OpenStudy (zarkon):

yes...it is 2 r-1 is the number of boys you pass so r-1=1 r=1+1=2

OpenStudy (knov):

that makes sense.

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} & \dfrac{0+1+\frac12+\frac13}{4} \hspace{.33em}\\~\\ \end{align}}\)

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