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The side length of the square is 8cm. I need help figuring out the radius of the inscribed and the circumscribed circles. Please help! I may not respond immediately, I may have to run soon.
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|dw:1459782475291:dw|
The inscribed circle is simple.
Alright. So its 4cm, really?
Right.
Now we need to look at the circumscribed circle.
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|dw:1459782643530:dw|
Use the Pythagorean theorem to find x, the radius of the circumscribed circle. |dw:1459782878745:dw|
Ok, I will. ALso, sorry for disapearing.
Is it 128?
\(a^2 + b^2 = c^2\) \(c^2 = a^2 + b^2\) \(x^2 = (4~cm)^2 + (4~cm)^2 \) \(x^2 = 16~cm^2 + 16~cm^2\) \(x^2 = 32~cm^2\) \(x = \sqrt{32~cm^2} \) \(x = \sqrt{16 \times 2~cm^2} \) \(x = 4\sqrt 2~cm\)
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