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Mathematics 16 Online
OpenStudy (thehollywoodstud):

Will fan and Medal Need Help!!!

OpenStudy (thehollywoodstud):

OpenStudy (janu16):

what are you trying to find?

OpenStudy (thehollywoodstud):

im not sure in all honesty

OpenStudy (janu16):

what does the question say?

OpenStudy (thehollywoodstud):

what i screen shotted thats it

OpenStudy (janu16):

ohhok

OpenStudy (thehollywoodstud):

yea sorry for the confusion

OpenStudy (janu16):

k wait

OpenStudy (janu16):

x+3)/3 = (y+2)/2 Multiply both sides of the equation by the Common Denominator 6 2x + 6 = 3y + 6 2x = 3 y x/3 = y/2

OpenStudy (janu16):

@thehollywoodstud

OpenStudy (thehollywoodstud):

so how do i do that?

OpenStudy (janu16):

what?

OpenStudy (janu16):

i just showed you

OpenStudy (mathstudent55):

This is a property of proportions. If \(\dfrac{a + b}{b} = \dfrac{c + d}{d} \), then \(\dfrac{a}{b} = \dfrac{c}{d} \)

OpenStudy (thehollywoodstud):

oh yeah your right my bad it was loading

OpenStudy (janu16):

talking to me?

OpenStudy (thehollywoodstud):

yea sorry ill tag you from now on. So whats the next step?

OpenStudy (thehollywoodstud):

@Janu16

OpenStudy (mathstudent55):

Here is another way of proving it: \(\dfrac{x + 3}{3} = \dfrac{y + 2}{2} \) Undo the sums: \(\dfrac{x}{3} + \dfrac{3}{3}= \dfrac{y}{2} + \dfrac{2}{2} \) \(\dfrac{x}{3} + 1= \dfrac{y}{2} + 1 \) Subtract 1 from both sides: \(\dfrac{x}{3}= \dfrac{y}{2} \)

OpenStudy (janu16):

@thehollywoodstud i said the answer was y/2

OpenStudy (thehollywoodstud):

can you help me with more? @mathstudent55

OpenStudy (mathstudent55):

Yes, but pls start a new post for each question.

OpenStudy (mathstudent55):

The answer is y/2

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