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OpenStudy (thehollywoodstud):
OpenStudy (janu16):
what are you trying to find?
OpenStudy (thehollywoodstud):
im not sure in all honesty
OpenStudy (janu16):
what does the question say?
OpenStudy (thehollywoodstud):
what i screen shotted thats it
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OpenStudy (janu16):
ohhok
OpenStudy (thehollywoodstud):
yea sorry for the confusion
OpenStudy (janu16):
k wait
OpenStudy (janu16):
x+3)/3 = (y+2)/2
Multiply both sides of the equation by the Common Denominator 6
2x + 6 = 3y + 6
2x = 3 y
x/3 = y/2
OpenStudy (janu16):
@thehollywoodstud
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OpenStudy (thehollywoodstud):
so how do i do that?
OpenStudy (janu16):
what?
OpenStudy (janu16):
i just showed you
OpenStudy (mathstudent55):
This is a property of proportions.
If \(\dfrac{a + b}{b} = \dfrac{c + d}{d} \), then \(\dfrac{a}{b} = \dfrac{c}{d} \)
OpenStudy (thehollywoodstud):
oh yeah your right my bad it was loading
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OpenStudy (janu16):
talking to me?
OpenStudy (thehollywoodstud):
yea sorry ill tag you from now on. So whats the next step?
OpenStudy (thehollywoodstud):
@Janu16
OpenStudy (mathstudent55):
Here is another way of proving it:
\(\dfrac{x + 3}{3} = \dfrac{y + 2}{2} \)
Undo the sums:
\(\dfrac{x}{3} + \dfrac{3}{3}= \dfrac{y}{2} + \dfrac{2}{2} \)
\(\dfrac{x}{3} + 1= \dfrac{y}{2} + 1 \)
Subtract 1 from both sides:
\(\dfrac{x}{3}= \dfrac{y}{2} \)
OpenStudy (janu16):
@thehollywoodstud i said the answer was y/2
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