I need help!!
A car with an initial velocity of 25 m/s [E] experiences an average acceleration of 2.5 m/s2 [W] for 2.0 ´ 101 s. At the end of this interval, the velocity is a. 5.0 ´ 101 m/s [W] b. 0.0 m/s c. 25 m/s [W] d. 75 m/s [W] e. 75 m/s [E]
@agent0smith
how do we do this question I forget
Final velocity = initial velocity + accel * time Keep in mind the directions.
oh
I get A
@FaiqRaees
for how many seconds does that acceleration lasts?
I got 5
Yeah I can't read the time either, so I can't check anything.
A car with an initial velocity of 25 m/s [E] experiences an average acceleration of 2.5 m/s^2 [W] for 2.0x10^1s. At the end of this interval, the velocity is a.5.0x10^1 m/s [W] b.0.0 m/s c.25 m/s [W] d.75 m/s [W] e.75 m/s [E]
@agent0smith know you can see better thou
So... 20 seconds. Just use Final velocity = initial velocity + accel * time And keep in mind the directions of velocity and acceleration. Make one negative.
I am having little trouble
@ParthKohli
@Astrophysics
@KendrickLamar2014
\[Final ~ velocity = Initial ~ velocity + Accel \times Time\] 1. What is the Initial Velocity? 2. What is the Acceleration? 3. What is the Time?
1. 25 2. 2.5 3. 2.00x10^1
Yes, now plug that in to get the answer.
LOL i am getting 550
vf= 25+2.5*2.00
\[25+(2.5)(2)(10^1)\] \[=25+5(10^1)\] \[=25+(5)(10)\] \[=25+50\] \[=75\]
The velocity and acceleration are in different directions. One of them needs to be negative.
yea the west side be negative then it be -2.5
I didnt know how to solve that part. @agent0smith thanks for that :)
It is C. [West] = (-) direction [East] = (+) direction a avg=Δv/Δt=vf−vot Plugging in given values: −2.5=vf−25/20 vf= -25 Solving for vf will give me −25, which means 25 [West] @agent0smith
agree?
Yes.
Join our real-time social learning platform and learn together with your friends!