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Physics 18 Online
OpenStudy (mtalhahassan2):

I need help!!

OpenStudy (mtalhahassan2):

A car with an initial velocity of 25 m/s [E] experiences an average acceleration of 2.5 m/s2 [W] for 2.0 ´ 101 s. At the end of this interval, the velocity is a. 5.0 ´ 101 m/s [W] b. 0.0 m/s c. 25 m/s [W] d. 75 m/s [W] e. 75 m/s [E]

OpenStudy (mtalhahassan2):

@agent0smith

OpenStudy (mtalhahassan2):

how do we do this question I forget

OpenStudy (agent0smith):

Final velocity = initial velocity + accel * time Keep in mind the directions.

OpenStudy (mtalhahassan2):

oh

OpenStudy (mtalhahassan2):

I get A

OpenStudy (mtalhahassan2):

@FaiqRaees

OpenStudy (faiqraees):

for how many seconds does that acceleration lasts?

OpenStudy (mtalhahassan2):

I got 5

OpenStudy (agent0smith):

Yeah I can't read the time either, so I can't check anything.

OpenStudy (mtalhahassan2):

A car with an initial velocity of 25 m/s [E] experiences an average acceleration of 2.5 m/s^2 [W] for 2.0x10^1s. At the end of this interval, the velocity is a.5.0x10^1 m/s [W] b.0.0 m/s c.25 m/s [W] d.75 m/s [W] e.75 m/s [E]

OpenStudy (mtalhahassan2):

@agent0smith know you can see better thou

OpenStudy (agent0smith):

So... 20 seconds. Just use Final velocity = initial velocity + accel * time And keep in mind the directions of velocity and acceleration. Make one negative.

OpenStudy (mtalhahassan2):

I am having little trouble

OpenStudy (mtalhahassan2):

@ParthKohli

OpenStudy (mtalhahassan2):

@Astrophysics

OpenStudy (mtalhahassan2):

@KendrickLamar2014

OpenStudy (kendricklamar2014):

\[Final ~ velocity = Initial ~ velocity + Accel \times Time\] 1. What is the Initial Velocity? 2. What is the Acceleration? 3. What is the Time?

OpenStudy (mtalhahassan2):

1. 25 2. 2.5 3. 2.00x10^1

OpenStudy (kendricklamar2014):

Yes, now plug that in to get the answer.

OpenStudy (mtalhahassan2):

LOL i am getting 550

OpenStudy (mtalhahassan2):

vf= 25+2.5*2.00

OpenStudy (kendricklamar2014):

\[25+(2.5)(2)(10^1)\] \[=25+5(10^1)\] \[=25+(5)(10)\] \[=25+50\] \[=75\]

OpenStudy (agent0smith):

The velocity and acceleration are in different directions. One of them needs to be negative.

OpenStudy (mtalhahassan2):

yea the west side be negative then it be -2.5

OpenStudy (kendricklamar2014):

I didnt know how to solve that part. @agent0smith thanks for that :)

OpenStudy (mtalhahassan2):

It is C. [West] = (-) direction [East] = (+) direction a avg=Δv/Δt=vf−vot Plugging in given values: −2.5=vf−25/20 vf= -25 Solving for vf will give me −25, which means 25 [West] @agent0smith

OpenStudy (mtalhahassan2):

agree?

OpenStudy (agent0smith):

Yes.

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