Question

Help please

Answer 1

first step looks good

Answer 2

second step is to square that sucker

Answer 3

How:/ could you help me through, I don't understand any of it

Answer 4

you got the derivative fine

Answer 5

No, those were hints

Answer 6

now you need \((f'(x))^2=(2x-\frac{1}{8x})^2\)

Answer 7

oh trouble with the derivative?

Answer 8

I don't know any of this

Answer 9

@satellite73

Answer 10

@robtobey

Answer 11

do you know how to take the derivative of \(x^2\)?

Answer 12

no:/

Answer 13

then skip this, there is no way on earth you can do it
you need to learn how to find derivatives first
that takes a couple weeks

Answer 14

then you have to learn how to integrate, that is usually in the next semester
derivatives you learn in calc 1, integrals calc II

Answer 15

I have to do this by tonight, I don't know any of this, my teacher does not help me

Answer 16

@satellite73

Answer 17

this is second semester calculus material, it takes one semester of calculus to learn about derivatives, another to learn about integrals
takes usually 28 weeks of 4 class hours per week to lean it,
can't do it in one night, or even one month of nights

Answer 18

what class are you taking?

Answer 19

Geometry:(

Answer 20

Could you teach me this? Because, I have to do this also

Answer 21

@satellite73

Answer 22

\(\theta\) is the arc length \(14\pi\) divided by the radius \(12\)

Answer 23

in other words \[\theta =\frac{14\pi}{12}\] which you can reduce

Answer 24

3.665 @satellite73