Mathematics
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OpenStudy (korosh23):
Pre-calculus 12 Question!
Logarithm function convert to exponential function!
Convert this to exponential form:
y= 2 log3 (2x)
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OpenStudy (anonymous):
you gottta bring in the two first
OpenStudy (anonymous):
i.e. start with \[y=\log_3(4x^2)\]
OpenStudy (korosh23):
this is what I think: 3^y/2 = 2x
OpenStudy (anonymous):
then \[y=\log_b(x)\iff b^y=x\]
OpenStudy (korosh23):
oh I did not know you can times the 2 out side with inside 2x?
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OpenStudy (anonymous):
you could write it your way, yes
OpenStudy (anonymous):
\[y=2\log_3(2x)\\
\frac{y}{2}=\log_3(2x)\\
3^{\frac{y}{2}}=2x\]
OpenStudy (korosh23):
I see
OpenStudy (anonymous):
which is the same as \[3^y=(2x)^2\\
3^y=4x^2\]
OpenStudy (korosh23):
yes
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OpenStudy (anonymous):
i used this first \[n\log_b(x)=\log_b(x^n)\]
OpenStudy (anonymous):
get the same answer of course
OpenStudy (korosh23):
just a quick check:
I looked up on desmos,
y= log3 (4x) does not equal y = 2 log 3 (2x)
OpenStudy (korosh23):
@satellite73
OpenStudy (anonymous):
no it doesn't
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OpenStudy (anonymous):
\[2\log(2x)=\log((2x)^2)=\log(4x^2)\]
OpenStudy (korosh23):
including base 3?
OpenStudy (anonymous):
including base your favourite number
base is irrelevant, it is a property of any log
OpenStudy (korosh23):
ok got it. Thank you :)
OpenStudy (anonymous):
yw