Question

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Answer 1

you need a picture? will help with the bounds

Answer 2

http://www.wolframalpha.com/input/?i=x^2,y%3D2-x

Answer 3

you can see that \(y=x-2\) is larger than \(x^2\) on that region, so you will have \[\int _a^b(2-x-x^2)dx\]

Answer 4

the limits of integration is where they intersect

Answer 5

thank you!! so the inetgral 0 to 2

Answer 6

oh no

Answer 7

the meet up where \[x^2=2-x\]

Answer 8

the integral 2 to 0 of (2−x) -x^2dx

Answer 9

no

Answer 10

you have to solve \[x^2=2-x\] to see where they meet

Answer 11

ohhh -2 and 1

Answer 12

yes, those

Answer 13

the integral 0 to 1 x^2dx- the integral 1 to 2 (2-x)dx