The coordinate plane below represents a city. Points A through F are schools in the city.
Part A: Using the graph above, create a system of inequalities that only contain points B and C in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Part B: Explain how to verify that the points B and C are solutions to the system of inequalities created in Part A. Part C: Lisa can only attend a school in her designated zone. Lisa's zone is defined by y > 2x + 5. Explain how you can identify the schools that Lisa is allowed to attend.
I'm not sure where you got this question from, but I answered this question word for word less than a week ago for another person, who had the same issue with their question: There is no shaded area to examine!
it says it will be shaded..
you have to create them
Ah, I understand. To get some grasp of your understanding, do you know how we'd start this problem? How would we find one of the two equations that would encompass B?
We would find the points on y and x
?? idk i think
Can you elaborate? Don't be afraid to be wrong, just try for me.
i guess where the points match up for b liek i guess y=1 and x=3 ?
Well, that'd be how we find the ordered pair for B. Do you know slope-intercept form?
isnt it y=mx+b but i dont remember how exactly to do it cuz my teacher never explains it to me ):
No worries! That's what we're here for! Now, as you just said, slope-intercept form is indeed "y=mx+b". In this equation, y and x do not change. You do not substitute anything for them (for our purposes tonight only). Thus we have 'm' and 'b' left. 'm' is equal to slope (or rise over run). There's a fancy equation for that too if needed. Then we have 'b'. There's no need to overthink 'b', just know that it is the value on the y axis you go through with the linear line y=mx+b creates. If no value is given for b, such as "y=5x", it's assumed that the y-intercept is at y=0. Similarly, if no value is placed next to the x, such as "y=x+4", it's assumed the slope is one. Follow so far?
yesss thankyou ;0;
Great! So, I'm gonna give you a quick example. If I have the line of y=2x+1, the equation is graphed as: http://goo.gl/aIdaPz. Notice the y-axis is intercepted by the linear equation at y=1. Then, each point is two units up and one unit right of the previous point. (As the slope is 2, aka 2/1). Follow?
yess
What part are you having trouble with? c:
All of it ):
Okay, for part one. You want to enclose points B and C within a geometric shape. That means that the first inequality will be X=2. As X=2 is a vertical line separating B and C from the other points.
Sorry. X>2
Then, your next inequality would be 4>X, as beyond that line, no relevant points exist. You don't want to enclose infinity. Are you following me?
yess thankyou ;0;
So, I'm going to ask you to do the next step. What horizontal inequality lines do you need to write down in order to enclose points B and C?
For reference, Y = 1,2,3....infinity are all going to be horizontal lines passing through Y.
srry it just glitched let me type it agian ;0;
for b it would be x=3 and y=1 and for a it would be x=3 and y=-3 ?? srry im so bad ;0;
It;s okay, you'll get there! No just quite right yet. You need to close /both/ B and C in an enclosed region. Don't be afraid to give them some space. Essentially you need to draw a rectangle around it. So. Your inequalities would be: 4 > x // 2 < x y > - 4 // 2 > y Please draw these lines on the graph and show me your working! c:
what does // represent? o-o
Nothing, just a divider. c:
4 > x 2 < x y > - 4 2 > y
so i put those on a graph?
Yes. c:
ookie one sec ;0;
Okay. c:
Is that good? ;0;
I'll be with you in a second, something came up!
That looks about right. c: What is your working for the second question? Part B?
what do i put for a tho??
Don;t you have the inequalities already? Just write those down. c:
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