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OpenStudy (shaleiah):
OpenStudy (shaleiah):
@Mehek14
jhonyy9 (jhonyy9):
first is x^(1/2) - yes ?
OpenStudy (welshfella):
sqrt x = x^1/2
so next term = x^(1/2 * 3/4)
jhonyy9 (jhonyy9):
the second what will be ?
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OpenStudy (welshfella):
third term = x^(1/2*3/4 * 3/4)
OpenStudy (shaleiah):
x^3/8
OpenStudy (welshfella):
that is correct fro the second term
OpenStudy (shaleiah):
x^9/32
jhonyy9 (jhonyy9):
yes this is the 3rd
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OpenStudy (welshfella):
yes
OpenStudy (welshfella):
yes x^(9/32) is the third term
OpenStudy (welshfella):
good job
OpenStudy (shaleiah):
Could you help with one more question jhonyy?
jhonyy9 (jhonyy9):
yes sure
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OpenStudy (shaleiah):
OpenStudy (shaleiah):
@anthonyym
OpenStudy (anthonyym):
Ok to get f(0) you simply plug 0 in as x and solve.
OpenStudy (shaleiah):
-7
OpenStudy (shaleiah):
@anthonyym
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OpenStudy (anthonyym):
Yes that's correct. Now compare that to what y equals in the graph. When x is 0, what is y in the graph?
OpenStudy (anthonyym):
|dw:1460497373749:dw|
OpenStudy (anthonyym):
In other words, where does the graph intersect x=0? That is where y is.
OpenStudy (shaleiah):
10
OpenStudy (anthonyym):
Really? Nothing crosses (0,10).
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OpenStudy (anthonyym):
I see it as -7.
OpenStudy (anthonyym):
I circled where the graph is at x=0.
OpenStudy (shaleiah):
Alright
OpenStudy (anthonyym):
Do you understand that? The graph is a visual representation of the y part (dependent variable) of the graph. You are trying to see where the graph (y) is when x=0.
OpenStudy (anthonyym):
And it also just so happens that x=0 is the same thing as the y-intercept. So you can answer the 2nd one too.
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OpenStudy (shaleiah):
I think I understand...
f > g
y > g
f < g
OpenStudy (shaleiah):
@anthonyym
OpenStudy (anthonyym):
Ok. The formula for where the x-coordinate at a parabola's minimum/maximum is
x = -b/(2a)
OpenStudy (anthonyym):
The function f(x) is in ax^2 + bx + c form, so the value of b is -11.
OpenStudy (anthonyym):
After you get the x value, substitute x back into f(x) = 6x^2 -11x -7 to get f(x). f(x) is the same as y.
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OpenStudy (anthonyym):
What did you get for x?
OpenStudy (shaleiah):
I got -11/12
OpenStudy (anthonyym):
yes -11/12 is right
OpenStudy (anthonyym):
Now plug that in as x and solve. You can use a calculator.
OpenStudy (shaleiah):
184.583
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OpenStudy (anthonyym):
I got something else.
OpenStudy (anthonyym):
Does your calculator have a store as variable option? You can store -11/12 as variable A. Type in -11/12 then hit STO-> A. Then type the equation into the calculator substituting x for A.
OpenStudy (anthonyym):
O man I'm sorry looking back you should have gotton x=11/12
OpenStudy (anthonyym):
x = -b/(2a) = -(-11)/(2*6) = 11/12
OpenStudy (shaleiah):
When I plug it in I get:
-12.041...
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OpenStudy (anthonyym):
Yes that's correct.
OpenStudy (anthonyym):
-12.041 is what y equals. Now compare that to what y equals at its minimum point on the graph g(x).
OpenStudy (anthonyym):
Need help?
OpenStudy (shaleiah):
yes
OpenStudy (anthonyym):
Ok so you know for the f(x) function, y=-12.041. For the g(x) function, even if there's no equation you can find the y-coordinate of the minimum. Do you now where the minimum of g(x) is on the graph?
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OpenStudy (anthonyym):
I have circled the minimum point in the attachment
OpenStudy (shaleiah):
-11
OpenStudy (anthonyym):
Yes that's correct. Now compare that minimum y-value to the value for f(x)
f(x) = -12.041
g(x) = -11
OpenStudy (shaleiah):
minimum value f(x) > g(x)
OpenStudy (anthonyym):
So
f(x) > g(x)
-12.041 > -11?
|dw:1460501261778:dw|
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OpenStudy (shaleiah):
yes
OpenStudy (anthonyym):
Is -2 greater than or less than -1
OpenStudy (shaleiah):
greater than
OpenStudy (anthonyym):
|dw:1460501603441:dw|
A number on the number line is always greater than any number on its left.