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Mathematics 10 Online
OpenStudy (shaleiah):

Please help!!

OpenStudy (shaleiah):

OpenStudy (shaleiah):

@Mehek14

jhonyy9 (jhonyy9):

first is x^(1/2) - yes ?

OpenStudy (welshfella):

sqrt x = x^1/2 so next term = x^(1/2 * 3/4)

jhonyy9 (jhonyy9):

the second what will be ?

OpenStudy (welshfella):

third term = x^(1/2*3/4 * 3/4)

OpenStudy (shaleiah):

x^3/8

OpenStudy (welshfella):

that is correct fro the second term

OpenStudy (shaleiah):

x^9/32

jhonyy9 (jhonyy9):

yes this is the 3rd

OpenStudy (welshfella):

yes

OpenStudy (welshfella):

yes x^(9/32) is the third term

OpenStudy (welshfella):

good job

OpenStudy (shaleiah):

Could you help with one more question jhonyy?

jhonyy9 (jhonyy9):

yes sure

OpenStudy (shaleiah):

OpenStudy (shaleiah):

@anthonyym

OpenStudy (anthonyym):

Ok to get f(0) you simply plug 0 in as x and solve.

OpenStudy (shaleiah):

-7

OpenStudy (shaleiah):

@anthonyym

OpenStudy (anthonyym):

Yes that's correct. Now compare that to what y equals in the graph. When x is 0, what is y in the graph?

OpenStudy (anthonyym):

|dw:1460497373749:dw|

OpenStudy (anthonyym):

In other words, where does the graph intersect x=0? That is where y is.

OpenStudy (shaleiah):

10

OpenStudy (anthonyym):

Really? Nothing crosses (0,10).

OpenStudy (anthonyym):

I see it as -7.

OpenStudy (anthonyym):

I circled where the graph is at x=0.

OpenStudy (shaleiah):

Alright

OpenStudy (anthonyym):

Do you understand that? The graph is a visual representation of the y part (dependent variable) of the graph. You are trying to see where the graph (y) is when x=0.

OpenStudy (anthonyym):

And it also just so happens that x=0 is the same thing as the y-intercept. So you can answer the 2nd one too.

OpenStudy (shaleiah):

I think I understand... f > g y > g f < g

OpenStudy (shaleiah):

@anthonyym

OpenStudy (anthonyym):

Ok. The formula for where the x-coordinate at a parabola's minimum/maximum is x = -b/(2a)

OpenStudy (anthonyym):

The function f(x) is in ax^2 + bx + c form, so the value of b is -11.

OpenStudy (anthonyym):

After you get the x value, substitute x back into f(x) = 6x^2 -11x -7 to get f(x). f(x) is the same as y.

OpenStudy (anthonyym):

What did you get for x?

OpenStudy (shaleiah):

I got -11/12

OpenStudy (anthonyym):

yes -11/12 is right

OpenStudy (anthonyym):

Now plug that in as x and solve. You can use a calculator.

OpenStudy (shaleiah):

184.583

OpenStudy (anthonyym):

I got something else.

OpenStudy (anthonyym):

Does your calculator have a store as variable option? You can store -11/12 as variable A. Type in -11/12 then hit STO-> A. Then type the equation into the calculator substituting x for A.

OpenStudy (anthonyym):

O man I'm sorry looking back you should have gotton x=11/12

OpenStudy (anthonyym):

x = -b/(2a) = -(-11)/(2*6) = 11/12

OpenStudy (shaleiah):

When I plug it in I get: -12.041...

OpenStudy (anthonyym):

Yes that's correct.

OpenStudy (anthonyym):

-12.041 is what y equals. Now compare that to what y equals at its minimum point on the graph g(x).

OpenStudy (anthonyym):

Need help?

OpenStudy (shaleiah):

yes

OpenStudy (anthonyym):

Ok so you know for the f(x) function, y=-12.041. For the g(x) function, even if there's no equation you can find the y-coordinate of the minimum. Do you now where the minimum of g(x) is on the graph?

OpenStudy (anthonyym):

I have circled the minimum point in the attachment

OpenStudy (shaleiah):

-11

OpenStudy (anthonyym):

Yes that's correct. Now compare that minimum y-value to the value for f(x) f(x) = -12.041 g(x) = -11

OpenStudy (shaleiah):

minimum value f(x) > g(x)

OpenStudy (anthonyym):

So f(x) > g(x) -12.041 > -11? |dw:1460501261778:dw|

OpenStudy (shaleiah):

yes

OpenStudy (anthonyym):

Is -2 greater than or less than -1

OpenStudy (shaleiah):

greater than

OpenStudy (anthonyym):

|dw:1460501603441:dw| A number on the number line is always greater than any number on its left.

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