Question

Can someone explain what I'm doing wrong?
http://prntscr.com/arw5ju
Got 78 for x which is the hypotenuse using cosine, so since I had x I was going to use sine to solve for y. I used sine and got 87 which is bigger than the hypotenuse. Why isn't my method working?

Answer 1

\(\cos 64^\circ = \dfrac{34}{x}\)

\(x = \dfrac{34}{ \cos 64^\circ} = 78\)

Your x is correct.

Answer 2

Use the method of completing the square to transform the quadratic equation into the equation form (x – p)^2 = q.

12 - 8x^2 + x^4 = 0

A) (x2 - 4)2 = -4

B) (x2 - 4)2 = 4

C) (x2 - 2)2 = -4

D) (x2 - 2)2 = 4

Answer 3

Thanks for your response cheesecake! However, we're told to use cosine, tan, or sine for this!

My x is correct? Good.

Answer 4

What equation did you use for y using sine?

Answer 5

y=78/64sin

Answer 6

@pizzaqueen5 GIMMIE ALL YOUR PIZZA

Answer 7

\(\sin \theta = \dfrac{opp}{hyp} \)

\(\sin 64^\circ = \dfrac{y}{77.5598}\)

\(y = 77.5598 \times \sin 64^\circ = 69.710\)

Answer 8

BTW, you can also use the tangent to find y without using the hypotenuse:

\(\tan 64^\circ = \dfrac{y}{34} \)

\(y = 34 \times \tan 64^\circ\)

Answer 9

Never mind. I asked a question and realized why it was wrong.

Thank you for your help!

Answer 10

You're welcome.