Question

.

Answer 1

I think I got 7.67

Answer 2

v(t)=-t^2+4
-t^2+4t+c
-3^2+4(3)+4
7
-0^2+4(0)
0
7

Answer 3

v=dx/dt

Answer 4

integrate v w.r.t.time to find the equation of x

Answer 5

Displacements= -21 ft which means the object traveled in the opposite direction at which it was projected :)

Answer 6

@ganeshie8

Answer 7

\[s=\int\limits_{0}^{3}(-t^2 +4) dt\]

Answer 8

\[s=(-t^3/3 +4t)_{0}^{3}\]

Answer 9

ohh 3?

Answer 10

let hum/her do the calculations please

Answer 11

him*

Answer 12

i was talking to @ijlal :)

Answer 13

@rvc was just trying to point out the mistake that she did as included the contact ' C ' ina definite integral didn't post the direct answer though anyways i am sorry :)

Answer 14

na na
i reminded u :)
what u were doing is alright buddy

Answer 15

@rvc alrighty then :)

Answer 16

thank you !!