Question

Can someone please see if I'm doing this wrong? Then problem is below

Answer 1

Notice that the figure has already been labeled. The variable x is used to represent the unknown width of the path. The area of the pool and the path combined is 672 square meters. Notice that the length of the combined area 18+2x and the width of the combined area is14+2x. If I recall the formula for a rectangle is area = length times width. We use the figure and the information given to write an equation for the area of the pool and path combined (14+2x)(18+2x)

Answer 2

\[(14+2x)(18+2x)=4x^2+252+?=672\]

Answer 3

I don't know how to get the third term in this equation

Answer 4

well umm
You kinda missed out on a big part there

(14+2x)(18+2x)=672 right?
So FOIL (14+2x)(18+2x) you get what?

Answer 5

Well whatever you get, let's just say it is\[yx^2+zx+a=672\]So to get it as a quadratic you subtract the 672 so it becomes\[yx^2+zx+a-672=0\]

Answer 6

And you would solve that like a regular quadratic

Answer 7

I got my answer by doing 2x first then timing 14 and 18 together

Answer 8

Oh I see how you do it now \[28+36x+4x^2\] Should be your answer

Answer 9

Umm no
You should get \[4x^2+64x+252=672\rightarrow4x^2+64x+252-672=0\]

Answer 10

\[4x^2+64x-420=0\]

Answer 11

@Atrineas Come and help it's your homework I can't finish

Answer 12

Oh okay @Brill I see now

Answer 13

Mathew how'd he get 64?

Answer 14

Because