How do I find the solution set?
x-2/x+4 = 2- 4/x

Question

How do I find the solution set?
 x-2/x+4 = 2- 4/x

-welp- · Answer

$$\frac{ x-2 }{ x+4 } = 2 - \frac{ 4 }{ x }$$

freckles · Answer

first make notice x+4 cannot be zero...we also must not have x be 0
otherwise those fractions bill be zero on bottom

anyways try getting rid of the fractions by multiplying both sides by x(x+4)

-welp- · Answer

I'm not sure what I'm supposed to do after -x^2-10x+16

I know the solution set is {-8,2} (I used mathway)

freckles · Answer

do you mean -x^2-10x+16=0
how did you get -10x?

-welp- · Answer

$$ \frac{ x-2 }{ x+4 } * x(x+4) = 2* x(x+4) - \frac{ 4 }{ x } * x(x+4) $$

$$x(x-2)= 2x(x+4) - 4(x+4)$$

$$x^2 -2x= 2x^2+8x-4x-16$$

$$x^2-6x=2x^2-16$$

$$x^2-6x+16=2x^2$$

$$-x^2-6x+16$$

This right?