Question

How do I find the solution set?
x-2/x+4 = 2- 4/x

Answer 1

\[\frac{ x-2 }{ x+4 } = 2 - \frac{ 4 }{ x }\]

Answer 2

first make notice x+4 cannot be zero...we also must not have x be 0
otherwise those fractions bill be zero on bottom

anyways try getting rid of the fractions by multiplying both sides by x(x+4)

Answer 3

I'm not sure what I'm supposed to do after -x^2-10x+16

I know the solution set is {-8,2} (I used mathway)

Answer 4

do you mean -x^2-10x+16=0
how did you get -10x?

Answer 5

\[ \frac{ x-2 }{ x+4 } * x(x+4) = 2* x(x+4) - \frac{ 4 }{ x } * x(x+4) \]

\[x(x-2)= 2x(x+4) - 4(x+4)\]

\[x^2 -2x= 2x^2+8x-4x-16\]

\[x^2-6x=2x^2-16\]

\[x^2-6x+16=2x^2\]

\[-x^2-6x+16\]

This right?