OpenStudy (marcelie):

Help Please... i got stuck on the values that i found and which would be my abs max/ min this is what i got

1 year ago
OpenStudy (marcelie):

1 year ago
OpenStudy (marcelie):

1 year ago
OpenStudy (marcelie):

@raffle_snaffle or anyone

1 year ago
OpenStudy (nicemathyguy):

Your derivative is wrong, it's $-2x^{-3}\ln x+\frac{x^{-2}}{x}$ Do you need more help to study the function given that?

1 year ago
OpenStudy (marcelie):

yes i found the derivative

1 year ago
OpenStudy (marcelie):

but idk if i did it correctly

1 year ago
OpenStudy (agent0smith):

@NiceMathyGuy marcelie's derivative is correct.

1 year ago
OpenStudy (nicemathyguy):

Ah sorry I misunderstood your answer. your answer is correct, and the function reaches its maximum in $e^{\frac{1}{2}}$ (it's increasing on $[\frac{1}{2},e^{\frac{1}{2}}]$ and decreasins on $[e^{\frac{1}{2}},4]$. So the min is reached either in $\frac{1}{2}$ or $4$.

1 year ago
OpenStudy (marcelie):

okay so how would i find the abs values ?

1 year ago
OpenStudy (marcelie):

|dw:1460834447992:dw|

1 year ago