OpenStudy (marcelie):

Help Please... i got stuck on the values that i found and which would be my abs max/ min this is what i got

1 year ago
OpenStudy (marcelie):
1 year ago

OpenStudy (marcelie):
1 year ago

OpenStudy (marcelie):

@raffle_snaffle or anyone

1 year ago
OpenStudy (nicemathyguy):

Your derivative is wrong, it's \[-2x^{-3}\ln x+\frac{x^{-2}}{x}\] Do you need more help to study the function given that?

1 year ago
OpenStudy (marcelie):

yes i found the derivative

1 year ago
OpenStudy (marcelie):

but idk if i did it correctly

1 year ago
OpenStudy (agent0smith):

@NiceMathyGuy marcelie's derivative is correct.

1 year ago
OpenStudy (nicemathyguy):

Ah sorry I misunderstood your answer. your answer is correct, and the function reaches its maximum in \[e^{\frac{1}{2}}\] (it's increasing on \[[\frac{1}{2},e^{\frac{1}{2}}]\] and decreasins on \[[e^{\frac{1}{2}},4]\]. So the min is reached either in \[\frac{1}{2}\] or \[4\].

1 year ago
OpenStudy (marcelie):

okay so how would i find the abs values ?

1 year ago
OpenStudy (marcelie):

|dw:1460834447992:dw|

1 year ago