Question

Hey, can someone help me with a few trig/pre-calc questions? I'll fan you and I'll medal you on each one (create different questions for each one) . I just need help to go through it. Thanks :)

Answer 1

Simply post your full question to get started. Please only post one question per thread to avoid lag and clutter

Answer 2

I will post in just a second. Im having a hard time with screenshot sorry

Answer 3

It hass been 20 minutes since you posted the question you're still having a problem posting a screenshot. If you want to know how to post a screenshot, check out this:
http://goo.gl/Xr1itf

Answer 4

sorry, my computer got wet and now it acts up from time to time. :P

Answer 5

That's ok. Take all the time you need.

Answer 6

Do you agree that
\[\Large \sin\left(\frac{1}{2}x\right)\]
is the same as
\[\Large 1*\sin\left(\frac{1}{2}x-0\right)+0\]
??

Answer 7

yes. right? im pretty sure anyway. ha, I used to love math and then they added words to it and i got confused XD

Answer 8

Notice how the color-coded terms match up
\[\Large {\color{red}{1}}*\sin\left({\color{blue}{\frac{1}{2}}}x-{\color{green}{0}}\right)+{\color{purple}{0}}\]
\[\Large {\color{red}{A}}*\sin\left({\color{blue}{B}}x-{\color{green}{C}}\right)+{\color{purple}{D}}\]
where...
|A| = amplitude
2pi/B = period
C/B = phase shift
y = D is the equation of the midline

Answer 9

thats right. its alwayts (2pi)/b isnt it?

Answer 10

yes the period is 2pi/B

in this case, B = 1/2 or you can think of it as B = 0.5 if fractions are a pain for you

Answer 11

so 1/2 pi

Answer 12

Period
\[\Large T = \frac{2\pi}{B}\]
\[\Large T = \frac{2\pi}{0.5}\]
\[\Large T = ???\]
leave the answer in terms of pi

Answer 13

2/0.5 is 4 soooo.... 4pi?

Answer 14

yep, you got it

Answer 15

cool well what if....okay ill ask you in the next question.